There are many other factors that can affect solubility, but these rules are a good first step to determine the outcome of aqueous solution reactions. The solubility rules are a useful guideline to predict whether a compound will dissolve or form a precipitate. The finished reaction is:Ģ KCl(aq) + Pb(NO 3) 2(aq) → 2 KNO 3(aq) + PbCl 2(s) This means PbCl 2 is insoluble and form a precipitate. Chlorides are soluble in water with the exception of silver, lead and mercury. KNO 3 will remain in solution since all nitrates are soluble in water. The products should rearrange the ions to: Using the third test tube, make a solution of sodium chloride, in the same way you prepared the first two solutions. Again, use a clean stir rod to mix the solution until all the salt is dissolved. To another test tube, add one spatula of potassium sulfate. What would be the expected products and will a precipitate form? Use a CLEAN glass stir rod to mix the solution until all the salt is dissolved. The resulting balanced reaction would be:Ģ AgNO 3(aq) + MgBr 2 → 2 AgBr(s) + Mg(NO 3) 2(aq) The other compound Mg(NO 3) 2 will remain in solution because all nitrates, (NO 3) -, are soluble in water. Are the products soluble in water?Īccording to the solubility rules, all silver salts are insoluble in water with the exception of silver nitrate, silver acetate and silver sulfate. The state of the products needs to be determined. The balanced reaction would be:Ģ AgNO 3(aq) + MgBr 2 → 2 AgBr(?) + Mg(NO 3) 2(?) For example, a silver nitrate solution (AgNO 3) is mixed with a solution of magnesium bromide (MgBr 2). The question remains, will AD or CB remain in solution or form a solid precipitate?Ī precipitate will form if the resulting compound is insoluble in water. This reaction is generally a double replacement reaction in the form: When two aqueous solutions are mixed, the ions interact to form products. These solutions are represented in chemical equations in the form: AB(aq) where A is the cation and B is the anion. This guide will show how to use the solubility rules for inorganic compounds to predict whether or not the product will remain in solution or form a precipitate.Īqueous solutions of ionic compounds are comprised of the ions making up the compound dissociated in water. (This is why wax is insoluble in water: it is non-polar, so the wax-wax interactions are weak, but the wax-water interactions are weaker than the water-water interactions.When two aqueous solutions of ionic compounds are mixed together, the resulting reaction may produce a solid precipitate. (Ionic salts are a good example: usually they have strong interactions in the solid and solvated states.) If the interactions in the solid are weak, the compound can still be insoluble in polar solvents if the interactions with the solvent are weaker than the Coulomb interactions of the solvent molecules with other solvent molecules. For instance, if it has very strong interactions between molecules or ions in the solid state, then it won't be very soluble unless the solvation interations are also very strong. Solubility depends on the relative stability of the solid and solvated states for a particular compound. (It's also a little funny because many salts aren't strong electrolytes, so teachers might be telling their students to write an equation that doesn't show what's really happening.) However, it does help show what it means to be a spectator ion, since they are the same on both sides when you write it like this. No real chemist would be likely to do this because it is a nuisance.
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